Test Series - computer fundamental

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Test Number 20/95

Q: Perform binary addition of 1101 + 0010 is ________
A. 1110
B. 1111
C. 0111
D. 1,1101
Solution: The addition is performed as :
1101
+ 0010
_______
1111
Therefore, the result is 1111.
Q: The addition 1+1 gives 0 as a result.
A. True
B. False
C. none
D. ...
Solution: The two result obtained is 0 with a carry of 1. This carry is transferred to the next higher column.
Q: The result of 0*1 in binary is ____________
A. 0
B. 1
C. invalid
D. 10
Solution: The binary multiplication of any number with 0 will give the result 0 itself. Any binary number when multiplied by 0 gives 0 only. e.g. 1101 * 0000 = 0000.
Q: The multiplication of 110 * 111 is performed. What is a general term used for 111?
A. Dividend
B. Quotient
C. Multiplicand
D. Multiplier
Solution: 111 is called the multiplier.
Whenever a multiplication is performed the second term is called the multiplier whereas the first term is called the multiplicand.
Q: The result obtained on binary multiplication of 1010 * 1100 is __________
A. 0001111
B. 0011111
C. 1111100
D. 1111000
Solution: The solution is as follows :
    1010
*  1100
________
       0000
     0000
   1010
1010
_______
1111000
Q: Which of the following is often called the double precision format?
A. 64-bit
B. 8-bit
C. 32-bit
D. 128-bit
Solution: The 64-bit format is referred to as the double precision format. It has 1 sign bit, 8 exponent bits and 23 bits for the mantissa.
Q: What do you call the intermediate terms in binary multiplication?
A. Multipliers
B. Mid terms
C. Partial Products
D. Multiplicands
Solution: The intermediate terms are called partial terms. The mid terms obtained in the binary multiplications are the partial ones whereas the answer obtained is called the final product.
Q: The result that is smaller than the smallest number obtained is referred to as ___________
A. NaN
B. Underflow
C. Smallest
D. Mantissa
Solution: It is referred to as underflow. Nan stands for not a number. Mantissa is the part after the decimal.
Q: The number of sign bits in a 32-bit IEEE format is _______
A. 1
B. 11
C. 9
D. 23
Solution: There is only 1 sign bit in all the standards. In a 32-bit format, there is 1 sign bit, 8 bits for the exponent and 23 bits for the mantissa.
Q: Express the decimal format of the signed binary number (101010)2 .
A. 10
B. 12
C. -12
D. -10
Solution: The first bit is the sign bit whereas the rest of the bits are magnitude bits. So the number is: 01010 =23 * 1 + 21 * 1 =8+2 =10.
But , the sign bit is 1,
Therefore the answer is : (-2)10.

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